Answer:
Hoang sent 22 texts
Jina sent 32 texts
Gorman sent 44 texts
Step-by-step explanation:
Let number of messages sent by
Jina be j
Gorman be g
Hoang be h
3 people total is 98, so we can write:
j + g + h = 98
Hoang sent 10 fewer than Jina, so we can write:
h + 10 = j
Giran sent 2 times as Hoang, so we can write:
g = 2h
Now, we substitute 2nd and 3rd equation in 1st and solve for h:
j + g + h = 98
h + 10 + 2h + h = 98
4h + 10 = 98
4h = 88
h = 22
We know j = h + 10, so j = 22 + 10 = 32
j = 32
And, we know g = 2h = 2(22) = 44
g = 44
