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Problem situation:
Anna is at the movie theater and has $35 to spend.
She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50.
How many snacks, x, can Anna buy?

Inequality that represents this situation:
9.50+3.50x≤35

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution. Pls explain where 2, -2, 4 and the rest of the numbers go. thx!

Respuesta :

Answer:

Amount of money Possessed by Anna = $ 35

Money spent on ticket = $9.50

Money spent on Snacks = $ 3.50

Let x number of snacks, which will be least number of snacks that Anna can buy.

transforming the situation in terms of inequality

→9.50 +3.50 x≤ 35

→9.50 -9.50+3.50 x≤35-9.50

→3.50 x≤25.50

Dividing both sides by 3.50, we get

→x≤7.3(approx)

which can't be number of Snacks, as it will be an integral value.

So, minimum number of snacks with given amount of money = 7

So, Anna can buy snacks(x)={x:x≤7,x=1,2,3,4,5,6,7}=At most 7.

Step-by-step explanation:

riodiana321

Answer:

solution to both: 2,4

solution to inequality ONLY: -2, 4.25 ,3 1/4

NOT a solution to both: 9 1/2

Step-by-step explanation:

i plugged in all the values and checked the answers

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