Answer:
3000 Joule of work is to be done.
Option: b
Explanation:
Given, mass of scooter = 20 Kg
Initial speed = 10 m/s, Final speed = 20 m/s, Work done = ΔE
Where, ΔE= change in kinetic energy
Solution:
[tex]\text { Kinetic Energy (initial) }=\frac{1}{2} \times \mathrm{mv}^{2}[/tex]
[tex]\text { Kinetic Energy (initial) }=\frac{1}{2} \times 20 \mathrm{Kg} \times(10 \mathrm{m} / \mathrm{s})^{2}[/tex]
[tex]\frac{1}{2} \times 200 \mathrm{Kg} \cdot \mathrm{m}^{2} / \mathrm{s}^{2}[/tex] = [tex]1000 \mathrm{Kg} \cdot \mathrm{m}^{2} / \mathrm{s}^{2}[/tex]
[tex]\text { Kinetic Energy (final) }=\frac{1}{2} \times m v^{2}[/tex]
[tex]\frac{1}{2} \times 20 \mathrm{Kg} \times(20 \mathrm{m} / \mathrm{s})^{2}[/tex]
[tex]\frac{1}{2} \times 20 \mathrm{Kg} \times 400 \mathrm{m}^{2} / \mathrm{s}^{2}[/tex]
[tex]\frac{1}{2} \times 8000 \mathrm{Kg} \cdot \mathrm{m}^{2} / \mathrm{s}^{2}[/tex]
[tex]4000 \mathrm{Kg} \cdot \mathrm{m}^{2} / \mathrm{s}^{2}[/tex]
Work done = ΔE = Kinetic Energy (final) - Kinetic Energy (initial)
Work done = ΔE = 4000 J - 1000 J work done = ΔE = 3000J
