Answer:
P(choosing a humbug ) =[tex](\frac{2x+6}{3x+9} )[/tex]
Step-by-step explanation:
Total number of Eclairs = 3
Total number of humbugs = 2x+ 6
Total number of mints = x
Let, E : Event of choosing a humbug out of the sweets jar
[tex]\textrm{P(E)} = \frac{\textrm{Total Number of favorable outcomes}}{\textrm{Total number of outcomes}}[/tex]
or,[tex]\textrm{P( Event of choosing a humbug )} = \frac{\textrm{2x+6}}{\textrm{3 + (2x+6) + x}}[/tex]
or, [tex]\textrm{P( Event of choosing a humbug )} = \frac{\textrm{2x+6}}{\textrm{3x+ 9}}[/tex]
Hence, P(choosing a humbug ) =[tex](\frac{2x+6}{3x+9} )[/tex]
