Answer:
It is not a probability distribution as some data is missing.
Step-by-step explanation:
It is not a probability distribution as some data is missing.
Since it is discrete and,
[tex]\sum_{x = 0}^{3}[/tex]P(X = x)
= (0.001 + 0.007 + 0.033 + 0.059)
= 0.1 ≠ 1
and we know that for
[tex]f_{X}(x) = P(X = x)[/tex]
to be classified as a discrete probability function,
1. 0 ≤ P(X = x) ≤ 1 and ∀ x ∈ R and
2. [tex]\sum_{x \epsilon M}[/tex]P(X = x) = 1
where M is the support of X or the set of points where P(X = x) > 0
must hold.