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Rank the members of each set of compounds according to the ionic character of their bonds. Most ionic bonds?a) PCl3 PBr3 PF3 Most ionic bonds? b) BF3 NF3 CF3 Most ionic bonds? c) SeF4 TeF4 BrF3 Least ionic bonds? d) PCl3 PBr3 PF3 Least ionic bonds?e) BF3 NF3 CF3 Least ionic bonds? f) SeF4 TeF4 BrF3

Respuesta :

Explanation:

More is the electronegativity difference between the combining atoms more polar is the compound. Hence, more ionic it will be in nature.

(a)   Electronegativity value of P = 2.19

Electronegativity value of Cl = 3.16

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a P-Cl bond = 3.16 - 2.19 = 0.97

Electronegativity difference of a P-Br bond = 2.96 - 2.19 = 0.77

Electronegativity difference of a P-F bond = 3.98 - 2.19 = 1.79

Since, a P-F bond has the highest electronegativity difference. Therefore, [tex]PF_{3}[/tex] is the most ionic compound and [tex]PBr_{3}[/tex] is the least ionic compound.

(b)   Electronegativity value of B = 2.04

Electronegativity value of N = 3.04

Electronegativity value of C = 2.55

Electronegativity value of F = 3.98

Electronegativity difference of a B-F bond = 3.98 - 2.04 = 1.94

Electronegativity difference of a N-F bond = 3.04 - 3.98 = 0.94

Electronegativity difference of a C-F bond = 3.98 - 2.55 = 1.43

Since, a B-F bond has the highest electronegativity difference. Therefore, [tex]BF_{3}[/tex] is the most ionic compound and [tex]NF_{3}[/tex] is the least ionic compound.

(c)   Electronegativity value of Se = 2.55

Electronegativity value of Te = 2.1

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a Se-F bond = 3.98 - 2.55 = 1.43

Electronegativity difference of a Te-F bond = 3.98 - 2.1 = 1.88

Electronegativity difference of a Br-F bond = 3.98 - 2.19 = 1.02

Since, a Te-F bond has the highest electronegativity difference. Therefore, [tex]TeF_{4}[/tex] is the most ionic compound and [tex]BrF_{3}[/tex] is the least ionic compound.

pstnonsonjoku

The higher the electronegativity difference between atoms, the higher the ionic character (polarity) of the bond.

The polarity of covalent bonds depends on the magnitude of electronegativity difference between the atoms. The greater the magnitude of  electronegativity difference between the atoms, the more the polarity of the bonds.

The ranking of the molecules in each set in order of decreasing polarity is;

  • PF3 > PCl3 >  PBr3
  • BF3 > CF3  > NF3
  • TeF4 > SeF4 >  BrF3

Learn more: https://brainly.com/question/1527403

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