Answer:
[tex]m_2=2554.83\ kg[/tex]
Explanation:
Given that,
Mass of the car, [tex]m_1=2200\ kg[/tex]
Initial speed of the car, [tex]u=3.6\ m/s[/tex]
Final speed of the car, [tex]v=3.1\ m/s[/tex]
To find,
The maximum mass of grain that it can accept.
Solution,
We know that according to the law of conservation of momentum, the initial momentum is equal to the final momentum.
[tex]m_1u=m_2v[/tex]
[tex]m_2=\dfrac{m_1u}{v}[/tex]
[tex]m_2=\dfrac{2200\times 3.6}{3.1}[/tex]
[tex]m_2=2554.83\ kg[/tex]
Therefore, the maximum mass of grain that it can accept is 2554.83 kg. Hence, this is the required solution.
