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A 5.75 × 107 kg battle ship originally at rest fires a 1100-kg artillery shell horizontally with a velocity of 550 m/s. show answer No Attempt 50% Part (a) If the shell is fired straight aft (toward the rear of the ship), there will be negligible friction opposing the ship’s recoil. Calculate the recoil velocity of the ship, in meters per second, taking the firing direction to be the positive direction.

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Answer:

-0.01052 m/s

Explanation:

M = mass of ship = [tex]5.75\times 10^7\ kg[/tex]

m = mass of shell = 1100 kg

v = velocity of shell = 550 m/s

u = recoil velocity of ship

As linear momentum is conserved

[tex](M - m)u=-mv\\\Rightarrow u=-\frac{mv}{M - m}\\\Rightarrow u=-\frac{1100\times 550}{5.75\times 10^7+1100}\\\Rightarrow u=-0.01052\ m/s[/tex]

The recoil velocity of the ship taking the firing direction to be the positive direction is -0.01052 m/s

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