Answer:
a) v = 1.7 m/s
b) s = 18.75 m
Explanation:
Given,
a)
The initial velocity of Mr. Comer, u = 0.8 m/s
The acceleration of Mr. Comer, a = 0.06 m/s²
The duration of his travel, t = 15 s
Using the first equation of motion,
v = u + at
= 0.8 + 0.06 (15)
= 1.7 m/s
Hence the final velocity of Mr.Comer, v = 1.7 m/s
b)
Using the second equations of motion
s = ut + 1/2 at²
= 0.8 (150 + 0.5 x 0.06 (15)²
= 18.75 m
Hence, the distance traveled by Mr. Comer, s = 18.75 m
