A satellite in a circular orbit 844.5 mi above the earth makes one complete orbit every 85.22 min. What is its linear velocity in​ mi/min? Use 3963 mi for the length of the radius of the earth and round to the nearest hundredth of a mile per minute.

Respuesta :

Answer: 354.5 mi/min

Explanation:

from the question we are given the following:

distance from the surface of the earth (s) = 844.5 mi = 1359091 m

radius of the earth (r) = 3963 mi = 6377830

time = 85.22 min = 5113.2 s

linear velocity = ?

distance of the satellite from the center of the earth (R) = 1359091 + 6377830

= 7736921 m

angular velocity = [tex]\frac{θ}{t}[/tex]

where θ = 2π

angular velocity = [tex]\frac{2π}{5113.2 }[/tex] = 0.00123 [tex]\frac{rad}{s}[/tex]

linear velocity = angular velocity x distance of satellite from the earth

linear velocity = 0.00123 x 7736921  

= 9507.3 m/s x  60/309.34 = 354.5 mi/min