Answer:
b) [tex]v=311.04 \,m.s^{-1}[/tex]
c) [tex]s=241864704\,m[/tex]
Explanation:
Given:
Force, [tex]F=0.1 \,N[/tex]
mass, [tex]m=500\,kg[/tex]
acceleration, [tex]a=2\times 10^{-4} \,m.s^{-2}[/tex]
initial velocity, [tex]u=0\,m.s^{-1}[/tex]
time, [tex]t=18\,days=(18\times 24\times 60\times 60)\,s[/tex]
(b)
Speed of the boat after 18 days:
[tex]v=u+a.t[/tex]
[tex]v=0+2\times 10^{-4} \times (18\times 24\times 60\times 60)[/tex]
[tex]v=311.04 \,m.s^{-1}[/tex]
(c)
Distance traveled in 18 days:
using the equation of motion
[tex]v^2=u^2+2a.s[/tex]
[tex]311.04^2=0^2+2\times 2\times 10^{-4}\times s[/tex]
[tex]s=241864704\,m[/tex]