Answer:
\frac{1}{230230}
Step-by-step explanation:
Given that in a certain lottery, an urn contains balls numbered 1 to 26
From this urn, 6 balls are chosen randomly, without replacement.
Bet amount 1 dollar and he selects a set of six numbers.
If these match with those chosen from the urn he wins (order does not matter)
Total ways of choosing 6 out of 26 = [tex]26C6 = \frac{26!}{20!6!} \\=230230[/tex]
The way he selects = 1
Hence probability of winning =[tex]\frac{1}{230230}[/tex]
with one ticket
