Answer:
F = 8 N
Explanation:
Given,
The mass of the smaller block, m = 20 Kg
The mass of the larger block, M = 96 Kg
The coefficient of the static friction, μ = 0.4
The static friction force acting on a body is the minimum horizontal force that is required to keep the smaller block from slipping down the larger block. It is given by the formula,
F = μ · η N
Where, η - normal force acting on the body
F = 0.5 x 20
= 8 N
Hence, the minimum horizontal force that is required to keep the smaller block from slipping down the larger block is, F = 8 N.
