An rock is dropped from a 202-foot platform. Use the projectile formula to determine when the rock hit the ground. Note that since the rock is dropped, v0=0.


The rock will hit the ground after how many seconds?

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The rock will hit the ground after 3.54 seconds.

Step-by-step explanation:

In this question the rock experiences a free fall with only gravity acting on it. The height of the fall is 202 ft and initial velocity is 0, thus the distance the object falls, h, is given by;

h= 1/2 gt² where t is time taken for the rock to hit the ground and g is acceleration due to gravity given as g=9.8 m/s²

First change feet to meters: divide the distance in feet by 3.281

202/3.281 =61.57 m

h=1/2 gt²

61.57= 1/2 * 9.8 * t²

61.57=4.9 t²

61.57/4.9=t²

12.57=t²

√12.57=t

3.54 sec=t

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