Answer:
[tex]h = 1.75 m[/tex]
Explanation:
As we know that height of the slide is given as
[tex]h = 1.80 m[/tex]
so time taken by the child to hit the water from the slide is given as
[tex]t = \sqrt{\frac{2h}{g}}[/tex]
now we will plug all data in it
[tex]t = \sqrt{\frac{2(1.80)}{9.81}}[/tex]
[tex]t = 0.605 s[/tex]
now we know that the horizontal distance moved by it is given as
[tex]L = v_x t[/tex]
[tex]3.55 = 0.605 v_x[/tex]
[tex]v_x = 5.86 m/s[/tex]
now by energy conservation
[tex]mgh = \frac{1}{2}mv^2[/tex]
so height of point A is given as
[tex]h = \frac{v_x^2}{2g}[/tex]
[tex]h = \frac{5.86^2}{2(9.81)}[/tex]
[tex]h = 1.75 m[/tex]
