contestada

What is the initial volume, in mL needed to prepare 150 mL of 3.0% (m/v) glucose from 22% (m/v) glucose

Respuesta :

Answer:

we all know that V1S1=V2S2

Explanation:

Now V2=150ml

         S2=3%

          S1=22%

           V1=?

                    V1S1=V2S2

                     V1=V2S2/S1

                     V1=  150*3/22

                          =   20.45ml

The initial volume needed to prepare 150ml 3%glucose from 22%glucose is 20.45ml.

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