Answer:
The magnitude of induced emf in the circuit is 0.0025 V
the coil resistance is 5 Ω is 0.0005 A
Explanation:
The length of coil l = 0.25 m
The flux by Faraday's Law Φ = B A
where
B = magnetic field (T)
A = Area ([tex]m^{2}[/tex])
induced emf in the circuit (ε)
ε = - dΦ/dt
= - A dB/dt
= [tex]l^{2}[/tex] dB/dt
= [tex](0.25)^{2}[/tex] (-0.04)
= 0.0025 V
The induced current with 5 Ω of resistance
I = ε/R
where
I = current (A)
R = Resistance (Ω)
thus,
I = (0.0025)/5
= 0.0005 A
