Find the dimensions of the box described.
The length is twice as long as the width. The height is 4 inches greater than the width. The volume is 720 cubic inches.

Respuesta :

The dimensions of the box are 6 inches, 12 inches and 10 inches

Step-by-step explanation:

There is a box, with dimensions length, width and height

  • The length is twice as long as the width
  • The height is 4 inches greater than the width
  • The volume is 720 cubic inches

We need to find its dimensions

Assume that the width of the box is x

∵ The width of the box is x

∵ The length is twice as long as the width

- Twice means times 2

∴ The length of the box = 2(x) = 2x

∵ The height is 4 inches greater than the width

- 4 inches greater means add 4

∴ The height of the box = x + 4

∵ The volume of the box = length × width × height

∵ length = 2x , width = x , height = x + 4

∴ The volume of the box = (2x) × (x) × (x + 4)

∵ (2x) × (x) = 2x²

∵ 2x²(x + 4) = (2x²)(x) + (2x²)(4) = 2x³ + 8x²

∴ The volume of the box = 2x³ + 8x²

∵ The volume of the box is 720 inches³

∴ 2x³ + 8x = 720

- Subtract 720 from both sides

2x³ + 8x² - 720 = 0

- Use your calculator to solve the equation and find the value of x

x = 6

∴ The width of the box = 6 inches

∴ The length of the box = 2(6) = 12 inches

∴ The height of the box = 6 + 4 = 10 inches

The dimensions of the box are 6 inches, 12 inches and 10 inches

Learn more:

You can learn more about volume in brainly.com/question/12497249

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