Answer:
Time it took for the walker to land on net = 1.75 seconds
Step-by-step explanation:
Given:
Height above the ring as a function of time is give as:
[tex]h(t)=60-16t^2[/tex]
Height of the tightrope walker after he falls = 11 feet
Plugging the height in order to find the time it took for the walker to land on net.
[tex]11=60-16t^2[/tex]
Adding [tex]16t^2[/tex] to both sides.
[tex]11+16t^2=60-16t^2+16t^2[/tex]
[tex]11+16t^2=60[/tex]
Subtracting both sides by 11.
[tex]11-11+16t^2=60-11[/tex]
[tex]16t^2=49[/tex]
Dividing both sides by 16.
[tex]\frac{16t^2}{16}=\frac{49}{16}\\\\t^2=\frac{49}{16}[/tex]
Taking square root both sides.
[tex]\sqrt t^2=\sqrt{\frac{49}{16}}\\\\t=\pm\frac{7}{4}[/tex]
Since time is always positive
∴ [tex]t=\frac{7}{4} = 1.75 \ seconds[/tex]
∴ Time it took for the walker to land on net = 1.75 seconds
