Answer:
[tex]\large \boxed{\text{932 mmHg}}[/tex]
Explanation:
The volume and amount are constant, so we can use Gay-Lussac’s Law:
At constant volume, the pressure exerted by a gas is directly proportional to its temperature.
[tex]\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}[/tex]
Data:
p₁ = 861 mmHg; T₁ = 5 °C
p₂ = ?; T₂ = 28 °C
Calculations:
(a) Convert the temperatures to kelvins
T₁ = ( 5 + 273.15) K = 278.15 K
T₂ = (28 + 273.15) K = 301.15 K
(b) Calculate the pressure
[tex]\begin{array}{rcl}\dfrac{861}{278.15} & = & \dfrac{p_{2}}{301.15}\\\\3.095 & = & \dfrac{p_{2}}{301.15}\\\\3.095\times301.15&=&p_{2}\\p_{2} & = & \mathbf{932}\end{array}\\\text{The new pressure reading will be $\large \boxed{\textbf{932 mmHg}}$}[/tex]
