Answer:
For the given expression [tex](\frac{1}{3})x + (\frac{2}{3}) = (\frac{1}{4})x - (\frac{1}{6})[/tex] , x = -10
Step-by-step explanation:
Here, the given expression is : [tex](\frac{1}{3})x + (\frac{2}{3}) = (\frac{1}{4})x - (\frac{1}{6})[/tex]
Now, solving for x:
Separate the terms with x on one side, we get
[tex](\frac{1}{3})x - (\frac{1}{4})x = - (\frac{1}{6}) - (\frac{2}{3})[/tex]
or, [tex](\frac{1}{3} - \frac{1}{4})x = - (\frac{1}{6} + \frac{2}{3})\\\implies (\frac{4-3}{(3)(4)}) x = -(\frac{1+ 2(2)}{6} )[/tex]
or, [tex]\frac{1}{12}x = - \frac{5}{6} \\\impliex x = -\frac{5}{6} \times 12 = -10[/tex]
or, x = -10
Hence, for the given expression [tex](\frac{1}{3})x + (\frac{2}{3}) = (\frac{1}{4})x - (\frac{1}{6})[/tex] , x = -10
