To solve this exercise we will need the concepts concerning impedance and capacitive reactance.
The potential in terms of impedance is given by,
[tex]V = I*\xi[/tex]
Where,
[tex]I = current\\\xi = Impedance[/tex]
Impedance is equal to
[tex]\xi = \frac{V}{I}[/tex]
[tex]\xi = \frac{175}{0.849}[/tex]
[tex]\xi = 206.12\Omega[/tex]
For definition we know that Impedance is equal also to
[tex]\xi = \frac{1}{Wc} = \frac{1}{2\pi f*c}[/tex]
Where f is the frequency and c the capacitive reactance.
Re-arrange for c, we have,
[tex]c = \frac{1}{2\pi f*\xi}[/tex]
[tex]c = \frac{1}{2\pi 61*206.12}[/tex]
[tex]c = 1.2658*10^{-5} F[/tex]
