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REASONING A rectangular box for a new product is designed in such a way that

the three dimensions always have a particular relationship defined by the variable x.

The volume of the box can be written as 6x + 31.x2 + 53x + 30, and the height is

always x + 2. What are the width and length of the box?

Respuesta :

sarajanethp

Answer:

(2x+3) y (3x+5)

Step-by-step explanation:

For this exercise we have that the volume is

V = 6x ^ 3 + 31X ^ 2 + 53x + 30

H = X + 2

The formula for the Volume its

V = H * L * W

for find L and W (width and length) we divide V / H = L * W

So,

[tex]\frac{V}{H} =\frac{6X^{3}+31X^{2}+53X+30 }{X+2}=(2x + 3) * (3x + 5)\\[/tex]

this division is in the attachment

so, L * W = (2x + 3) * (3x + 5)

Ver imagen sarajanethp

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