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Question 3 of 15

2 Points

A skydiver slows down from 54 m/s to 4 m/s by opening his parachute. If this

takes 0.75 seconds, what is the magnitude of the skydiver's acceleration?

O

O

A. 37.5 m/s?

B. 50 m/s

2

)

C. 66.7 m/s?

O

D. 9.8 m/s2

SUBMIT

Respuesta :

prozehus

Answer:

C. [tex]66.7m/s^{2}[/tex]

Step-by-step explanation:

We sholud also talk about medium aceleration

[tex]a_{m} =\frac{V_{f}-V_{i}}{t_{f}-t_{i}} = a_{m}=\frac{54-4}{0.75-0} = 66.7m/s^{2}[/tex]

NOTE : [tex]a=(v/t)=\frac{\frac{m}{s} }{s} =\frac{\frac{m}{s} }{\frac{s}{1} }=\frac{m*1}{s*s} = \frac{m}{s^{2} }[/tex] that are acceleration units

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