Respuesta :
Answer:
ΔQ = 11050.2 J
Explanation:
Assume mass of pan is 900 gm
Assuming mass of water is 100 gm
Assuming initial temperature of pan & water is Ti = 51.268 degree C
The final temperature is T_f = 77.7 degree C
The total energy required to raise temperature
[tex]E = (m_{pan}c_{pan} + m_{water} c_{water}) \Delta T[/tex]
E = [(900)(0.9) + (100)(4.2)](26.44)
E = 32521.2 J
The energy transferred is given by
ΔQ = E-W
ΔQ = 32521.2 J - 21471 J
ΔQ = 11050.2 J
The energy transferred due to a temperature difference will be 14115.36 Joules.
How to calculate energy
From the complete question, the initial temperature of pan and water is given as 51.268°C and the final temperature is given as 80.2°C.
The total energy required to raise the temperature will be:
E = 900(0.9) + (100 × 4.2 × 28.932)
= 35586.36 J
The energy transferred will now be:
= 35586.36 - 21471
= 14115.36 Joules.
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