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A telescope has an objective for focal length 800mm and eyepiece of focal 20 mm. It’s magnification will be

A telescope has an objective for focal length 800mm and eyepiece of focal 20 mm Its magnification will be class=

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Moalhazaa

Answer:

40X

Explanation:

M=F/f

M=800/20 ( the units cancel each other )

M=40X.

Magnification is the maximum size of the image that a given telescope can provide. The magnification of the given telescope will be 40X.

Magnification:

It is the maximum size of the image that a given telescope can provide. The formula of magnification is,

[tex]M=\dfrac Ff[/tex]

Where,

[tex]M[/tex]- magnification

[tex]F[/tex]- focal length of objective = 800 mm = 80 cm

[tex]f[/tex] - focal length of eyepiece = 20 cm

Put the values in the equation,

[tex]M = \dfrac {80}{20}\\\\M= 40 \rm X[/tex]

Therefore, the magnification of the given telescope will be 40X.

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