Using the probability concept, it is found that:
0.3 = 30% probability that a single randomly chosen value (from 1 to 100) would be over 70.
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Thus:
[tex]D = 30, T = 100, p = \frac{D}{T} = \frac{30}{100} = 0.3[/tex]
0.3 = 30% probability that a single randomly chosen value (from 1 to 100) would be over 70.
A similar problem is given at https://brainly.com/question/15536019
