Respuesta :
Answer:
y = (x - 2)(x + 4)(x - 1)
Step-by-step explanation:
Given the zeros of a function say x = a and x = b, then
The factors are (x - a) and (x - b) and
y = (x - a)(x - b)
Given the zeros are x = 2, x = - 4, x = 1, then
the factors are (x - 2), (x - (- 4)) and (x - 1), that is
(x - 2), (x + 4), (x - 1) , thus
y = (x - 2)(x + 4)(x - 1)
Answer:
[tex] y(x) = (x-2) (x-(-4)) (x-1)[/tex]
And if we implify we got:
[tex] y(x) = (x-2)(x+4)(x-1)[/tex]
And the correct option would be:
y = (x − 2)(x + 4)(x − 1)
Step-by-step explanation:
For this case we want a polynomial that satisfy the following zeros:
[tex] X= 2,-4,1 [/tex]
So then we need a polynomial of grade 3, and we can find the polynomial with this general formula:
[tex] y(x) = (x -a) (x-b) (x-c) ..... (x-k)[/tex]
Where [tex] a,b,c,...,k[/tex] represent the possible roots for the polynomial, if we replace we got:
[tex] y(x) = (x-2) (x-(-4)) (x-1)[/tex]
And if we implify we got:
[tex] y(x) = (x-2)(x+4)(x-1)[/tex]
And the correct option would be:
y = (x − 2)(x + 4)(x − 1)
