Answer:
The formula for aluminum(III) oxide is given by :[tex]Al_2O_3[/tex]
Explanation:
The formula for aluminum(III) oxide is given by :[tex]Al_2O_3[/tex]
In aluminum(III) oxide, aluminum (III) indicates that aluminium is present +3 valency in the compound.
Aluminum has atomic number of 13 and its electronic configuration is given as:
[tex][Al]=1s^22s^22p^63s^23p^1[/tex]
Aluminium atom will loose three electrons to attain noble gas configuration:
[tex][Al^{3+}]=1s^22s^22p^6[/tex]
[tex]Al\rightarrow Al^{3+}+3e^-[/tex]
where as oxygen has atomic number 8 and its electronic configuration is given by:
[tex][O]=1s^22s^22p^4[/tex]
Oxygen atom will gain 2 electrons to attain noble gas configuration:
[tex][Al^{3+}]=1s^22s^22p^6[/tex]
[tex]O+2e^-\rightarrow O^{2-}[/tex]
So, in the aluminium oxide, two aluminium atom swill donate their 3 electrons which will accepted by the three oxygen atoms respectively.
