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What is the period of rotation of Mars in seconds? (The period of rotation of Mars in hours is 24.6 hr.) s What is the angular velocity of Mars? (Enter the magnitude.) rad/s Given that Mars has a radius of 3.4 times 10^6 m at its equator, what is the linear velocity at Mars's surface? (Enter the magnitude of the linear velocity at the equator.) m/s

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AMB000

Answer:

[tex]T = 88560s[/tex]

[tex]\omega=7.1\times10^{-5}rad/s[/tex]

[tex]v=0.097m/s[/tex]

Explanation:

Since 1 hour has 60 minutes and 1 minute 60 seconds:

T = 24.6 hours = (24.6)(60)(60) seconds = 88560s

We use the formula for angular velocity for a revolution:

[tex]\omega=\frac{\Delta \theta}{\Delta t}=\frac{2\pi rad}{T}=\frac{2\pi rad}{88560s}=7.1\times10^{-5}rad/s[/tex]

Since the angular velocity is along the poles, the linear velocity at its equator can be obtained with:

[tex]v=r\omega=(3.4\times 10^6 m)(7.1\times10^{-5}rad/s)=0.097m/s[/tex]