(x + 7)² = x² + 14x + 49
The true statement that show the closure property of multiplication :
a. x² + 14x + 49 is a polynomial
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Further explanation
If equation ax³ + bx² + cx + d = 0 has roots x₁ , x₂ , and x₃ then
[tex]x_1 + x_2 + x_3 = - \frac{b}{a}[/tex]
[tex]x_1 x_2 + x_1 x_3 + x_2 x_3 = \frac{c}{a}[/tex]
[tex]x_1 x_2 x_3 = - \frac{d}{a}[/tex]
Let us now tackle the problem!
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This problem is about Polynomial.
[tex](x + 7)^2 = (x + 7)(x + 7)[/tex]
[tex](x + 7)^2 = x^2 + 7x + 7x + 7(7)[/tex]
[tex](x + 7)^2 = x^2 + 14x + 49[/tex]
[tex]x^2 + 14x + 49[/tex] is a polynomial.
[tex]x + 7[/tex] is polynomial.
It demonstrates the closure property of multiplication.
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Conclusion:
The true statement that show how the product of (x + 7)² demonstrates the closure property of multiplication:
a. x² + 14x + 49 is a polynomial
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Learn more
- Solving Quadratic Equations by Factoring : https://brainly.com/question/12182022
- Determine the Discriminant : https://brainly.com/question/4600943
- Formula of Quadratic Equations : https://brainly.com/question/3776858
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Answer details
Grade: High School
Subject: Mathematics
Chapter: Polynomial
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Keywords: Quadratic , Equation , Discriminant , Real , Number
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