Answer:
Acceleration, [tex]a=3.6\times 10^{16}\ m/s^2[/tex]
Explanation:
It is given that, two isolated protons are separated by 2 nm. The force due to charged particles is given by :
[tex]F_e=\dfrac{kq^2}{d^2}[/tex]
Force due to mass of proton, [tex]F_g=ma[/tex]
[tex]ma=\dfrac{kq^2}{d^2}[/tex]
[tex]a=\dfrac{kq^2}{md^2}[/tex]
[tex]a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.6\times 10^{-27}\times (2\times 10^{-9})^2}[/tex]
[tex]a=3.6\times 10^{16}\ m/s^2[/tex]
So, the acceleration of two isolated protons is [tex]3.6\times 10^{16}\ m/s^2[/tex]. Hence, this is the required solution.
