you want to swim straight across a river that is 76 m wide. youfind that you can do this if you swim 28degree upstream at aconstant rate of 1.5m/s relative to the water. at what rate doesthe river flow? The angle is measured from the river bank( directlyupstream is θ=0 degree while directly across the river isθ=90degree).

Respuesta :

Answer:

[tex]v_{water} = 1.325\ m/s[/tex]

Explanation:

given,                                          

width of river = 76 m                    

swimming at an angle = 28°                

constant rate of speed = 1.5 m/s        

rate at which river flow = ?                              

[tex]v_{water} = v_{max}\ cos \theta[/tex]                  

[tex]v_{water} = 1.5 \times\ cos 28^0[/tex]      

[tex]v_{water} = 1.5 \times 0.883[/tex]            

[tex]v_{water} = 1.325\ m/s[/tex]                    

hence, the rate of flow of river is equal to [tex]v_{water} = 1.325\ m/s[/tex]