Answer:
[tex]v_{water} = 1.325\ m/s[/tex]
Explanation:
given,
width of river = 76 m
swimming at an angle = 28°
constant rate of speed = 1.5 m/s
rate at which river flow = ?
[tex]v_{water} = v_{max}\ cos \theta[/tex]
[tex]v_{water} = 1.5 \times\ cos 28^0[/tex]
[tex]v_{water} = 1.5 \times 0.883[/tex]
[tex]v_{water} = 1.325\ m/s[/tex]
hence, the rate of flow of river is equal to [tex]v_{water} = 1.325\ m/s[/tex]