The required linear equation will be x = 5 that is perpendicular to y=5 and passing through the point (5, 4)
Complete question:
Give an example of a linear equation that is perpendicular to y=5 passing through the point (5, 4)
The standard form for calculating an equation of a straight line is expressed as y = mx+b
m is the slope of the line
b is the y-intercept
Given the equation y = 4
Write in standard form
y = 0x + 4
Get the slope of the line
mx = 0x
m = 0
This shows that the slope of the line is 0
The slope of the line perpendicular to the line will not exist.
We can write the required expression as x = a where a is the x-coordinate
of the point (5, 4).
This shows that a = 5
The required linear equation will be x = 5 that is perpendicular to y=5 and passing through the point (5, 4)
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