Answer:
The value of y is 3.
Step-by-step explanation:
[tex]DF[/tex] is a midsegment, by given.
[tex]AD=DB[/tex] and [tex]CF = FB[/tex], by midsegment definition.
Also, if [tex]DF[/tex] is a mid segment, then [tex]AC \parallel DF[/tex].
[tex]CF=6(y-1)[/tex] and [tex]FB=4y[/tex], by given.
Replacing each of the segments, we have
[tex]CF = FB[/tex]
[tex]6(y-1)=4y\\6y-6=4y\\6y-4y=6\\2y=6\\y=3[/tex]
Therefore, the value of y is 3.
