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A bicycle tire is spinning counterclockwise at 3.00 rad/s. During a time period Δt = 2.30 s, the tire is stopped and spun in theopposite (clockwise) direction, also at 3.00 rad/s. Calculate the change in the tire's angular velocity Δω and the tire's averageangular acceleration α. (Indicate the direction with the signs of your answers.)

Respuesta :

Answer:

Δω =  -6.00 rad/s

α = -2.61 m/s²

Explanation:

Step 1: Data given

A bicycle tire is spinning counterclockwise at 3.00 rad/s

Δt = 2.30 s

In theopposite (clockwise) direction, also at 3.00 rad/s

Step 2: Calculate the change in the tire's angular velocity Δω

Δω =  ωf -  ωi

ωf = - 3.00 rad/s

 ωi  = 3.00 rad/s

Δω =  ωf -  ωi  = -3.00 - 3.00 = -6.00 rad/s

Step 3: Calculate the tire's average angular acceleration α

α =  Δω /  ΔT

α = -6.00 rad/s /2.30s  

α = -2.61 m/s²

A negative angular acceleration means a decreasing angular velocity

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