Answer:
The answer to your question is below
Step-by-step explanation:
Data
3 shirts and 2 pair of pants
cost = $300
x = shirt price
y = pants price
a) 3x + 2y = 300
b) 2y = - 3x + 300
y = -3/2 x + 300/2
y = -3/2 x + 150
c) y = -3/2 (20) + 150
y = -30 + 150
y = 120 each of the pants costs $120
d) 3x + 2y = 300
if y = 0
3x = 300
x = 300/3
x = 100 It could be the highest cost of a shirt
e) 3x + 2y = 300
if x = 0
3(0) + 2y = 300
2y = 300
y = 300/2
y = 150 it could be the highest cost of a pair of pants.