Twice one number added to another numbers 18. if the second number id equal to 12 less than 4 times the first number, find the two numbers

Respuesta :

Answer:

The Answer is: The first number is 5 and the second one is 8.

Step-by-step explanation:

Let f = first number and s = second number

Twice the first number added to the second number is 18:

2f + s = 18

The second number is equal to 4 times the first number minus 12:

s = 4f - 12

Substitute:

2f + (4f - 12) = 18

6f - 12 = 18

6f = 18 + 12

6f = 30

f = 5, is the first number.

Solve for the 2nd number:

s = 4(5) - 12 = 20 - 12 = 8, is the second number.

Proof:

2f + s = 18

2(5) + 8 = 18

18 = 18

Hope this helps! Have an Awesome Day! :-)