Answer:
[tex]m_2=33833.33\ kg[/tex]
Explanation:
It is given that,
Mass of the train car, [tex]m_1=8700\ kg[/tex]
Initial speed of the train car, [tex]u_1=11\ m/s[/tex]
Initial speed of the second car, [tex]u_2=2.2\ m/s[/tex]
After the collision, both cars stick together and move off with a speed of 4.00 m/s, V = 4 m/s
Let [tex]m_2[/tex] is the mass of the second car. It can be calculated using the conservation of momentum. In case of inelastic collision, after collision both objects move with a common speed.
[tex]m_1u_1+m_2u_2=(m_1+m_2)V[/tex]
[tex]m_1u_1+m_2u_2=m_1V+m_2V[/tex]
[tex]m_1(u_1-V)=m_2(V-u_2)[/tex]
[tex]m_2=\dfrac{m_1(u_1-V)}{(V-u_2)}[/tex]
[tex]m_2=\dfrac{8700(11-4)}{(4-2.2)}[/tex]
[tex]m_2=33833.33\ kg[/tex]
So, the mass of the second car is 33833.33 kg. Hence, this is the required solution.