Answer:
[tex]y =- \frac{3}{2} x+1[/tex]
Step-by-step explanation:
The equation of the given straight line is 2x - 3y + 15 = 0.
Now, we can express the equation as 3y = 2x + 15
⇒ [tex]y = \frac{2}{3} x+ 5[/tex] ..........(1)
The equation is in slope-intercept form and the slope is =[tex]\frac{2}{3}[/tex]
Therefore, the equation of a straight line which is perpendicular to (1) is
[tex]y = -\frac{3}{2} x+c[/tex] {Where c is any constant}
{Since, the product of slopes of two perpendicular straight lines is -1}
Now, putting c = 1, we get the equation as [tex]y =- \frac{3}{2} x+1[/tex]. (Answer)
