Answer:
669042 N upward
Explanation:
[tex]W_g[/tex] = Work done by gravity on pile driver
[tex]W_b[/tex] = Work done by beam
u = Initial velocity
v = Final velocity
m = Mass of pile driver = 2200 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height the pile driver falls = 4.2 m
d = Bend in beam = 14 cm
Total work done = Change in Kinetic energy
[tex]W_g+W_b=\frac{1}{2}m(v^2-u^2)\\\Rightarrow mg(h+d)+Fd=0\\\Rightarrow F=-\frac{mg(h+d)}{d}\\\Rightarrow F=-\frac{2200\times 9.81(4.2+0.14)}{0.14}\\\Rightarrow F=-669042\ N[/tex]
The force the beam exerts on the pile driver while the pile driver is brought to rest is 669042 N upward
