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Find three consecutive integers such that the sum of the first, twice the second, and three times the third is -76.

Respuesta :

Answer:

Step-by-step explanation:

n+2(n+2)+3(n+4)=-76

n+2n+4+3n+12=-76

6n=-76-16

6n=-92

n=15,

n+2=17

n+4=19

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