100 points! please help!!!
A plane flies due north (90° from east) with a velocity of 100 km/h for 2 hours. During this time, a steady wind blows southeast at 30 km/h at an angle of 315° from due east. After 2 hours, where will the plane’s position be relative to its starting point? Show your work.

100 points please help A plane flies due north 90 from east with a velocity of 100 kmh for 2 hours During this time a steady wind blows southeast at 30 kmh at a class=

Respuesta :

Answer:

Explanation:

A plane flies due north (90° from east) with a velocity of 100 km/h for 2 hours.

With no wind, it will be 100*2 = 200 km north of its starting point.

But a steady wind blows southeast at 30 km/h at an angle of 315° from due east.

So the wind itself will blow the plane 30*2 = 60km at an angle of 315° from due east.

That is the same as 60*cos315° = 42.43km due east and 60*sin315° = -42.43km north.

Combining, the plane is at 42.43km due east and 200-42.43 = 157.57km due north from its starting point.

Answer:

Explanation:

ur pic shows the net velocity of plane

315deg from east means the inside angle of the triangle is 45deg

eastbound distance traveled is 30xcos45deg.x2 = 42.4264km

northboud distance traveled is (100-30xcos45deg.)x2 = 157.5736km