Answer:
1) [tex]x=-\frac{1}{3}, x=\frac{5}{2}[/tex]
2) [tex]x=1, x=\frac{3}{4}[/tex]
Step-by-step explanation:
1)
Given
[tex]f(y)= 6x^{2} -13x-5=0[/tex]
Equating above equation.
[tex]6x^{2} +2x-15-5=0[/tex]
[tex]2x(3x+1)-5(3x+1)=0[/tex]
[tex](3x+1)(2x-5)=0[/tex]
Solving for both the equation
[tex]3x+1=0[/tex]
[tex]3x=-1[/tex]
[tex]x=-\frac{1}{3}[/tex]
[tex]2x-5=0[/tex]
[tex]2x=5[/tex]
[tex]x=\frac{5}{2}[/tex]
[tex]x=-\frac{1}{3} ,x=\frac{5}{2}[/tex]
2)
Given
[tex]f(y)=4x^{2} -7x+3=0[/tex]
[tex]4x^{2} -4x-3x+3=0[/tex]
[tex]4x(x-1)-3(x-1)=0[/tex]
[tex](x-1)(4x-3)=0[/tex]
Solving for both equation
[tex]x-1=0[/tex]
[tex]x=1[/tex]
[tex]4x-3=0[/tex]
[tex]4x=3[/tex]
[tex]x=\frac{3}{4}[/tex]
[tex]x=1, x=\frac{3}{4}[/tex]
