Answer: The values of x and y are x = 12 and y = 24.
Step-by-step explanation:
Let x liter pure acid and y liter 10% acidic solution.
[tex]x + y = 36[/tex] ------------------(1)
[tex]x + 0.10y = 0.40\times 36=14.4[/tex] -----------------(2)
solve for x and y
From eq(1), we get that
[tex]x=36-y[/tex]
Put in eq(2), we get
[tex]36-y+0.10y=14.4\\\\-0.9y=14.4-36\\\\-0.9y=-21.6\\\\y=\dfrac{21.6}{0.9}\\\\y=24[/tex]
x=36-24=12
Hence, the values of x and y are x = 12 and y = 24.
