Answer:
1. Wf= 627.9 J
2. Wg= 416.32J
3. Work done by normal force = 0 always
4. Wk = 192.3J
5. Wt = 19.28 J
Explanation:
The question have no questions specific so here some possible questions:
1) Calculate the work done on the suitcase by the force F
2) Calculate the work done on the suitcase by the gravitational force.
3) Calculate the work done on the suitcase by the normal force.
4) Calculate the work done on the suitcase by the friction force.
5) Calculate the total work done on the suitcase.
1)
work = F * d
Wf= 161N * 3.90m
Wf= 627.9 J
2)
work = mgh
Wg= 20kg*9.8m/s² * 3.9m*sin33º
Wg= 416.32J
3)
Work done by normal force = 0 always
4)
friction work = µmgdcosΘ
Wk = 0.30*20kg* 9.8m/s²*3.90m*cos33º
Wk = 192.3J
5)
total work = (627.9- 416.32- 192.3) J
Wt = 19.28 J
Complete question
1) Calculate the work done on the suitcase by the force F
2) Calculate the work done on the suitcase by the gravitational force.
3) Calculate the work done on the suitcase by the normal force.
4) Calculate the work done on the suitcase by the friction force.
5) Calculate the total work done on the suitcase.
The work done on the suitcase by the force F is 627.9Joules
The work done on the suitcase by the gravitational force is 416.32Joules
The work done on the suitcase by the normal force is 0Joules
The work done on the suitcase by the friction force is 192.32 Joules
The total work done on the suitcase is 19.26Joules
The formula for calculating the work done by a body is expressed as:
Workdone = Force × distance
1) Work done on the suitcase = Horizontal force × distance traveled by the suitcase along the ramp.
Work done on the suitcase = 161 × 3.90
Work done on the suitcase = 627.9Joules
2) work done my gravitation= gravitational force × distance traveled along the ramp
Since gravitational force = mg
work done by gravitation = mghsinθ
Substitute the given parameters
work done by gravitation = 20×9.8×3.90sin33
work done by gravitation = 196×2.124
Work done by gravitation = 416.32Joules
3) If the force is normal to the plane then θ = 90degrees
Work done by normal force = 20×9.8×3.90sin0
work done by normal force = 196×0
Work done by normal force = 0Joules
4) Frictional force = μRcosθ
Frictional force = μmgcosθ
Work done by friction = Frictional force × height
work done by friction = μmgcosθ × h
Work done by friction = 0.3 × 20 × 9.8 × cos33 × 3.9
Work done by friction = 229.32cos33
Work done by friction = 192.32 Joules
5) The total work done is the sum of all the forces acting on the suitcase.
Since the work done by gravitation and friction are both acting in the negative direction, hence;
Total work done = 627.9 + (-416.32) + 0 + (-192.32)
Total work done = 627.9 - 416.32 - 192.32
Total workdone on the suitcase = 19.26Joules
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