For this case we have the following system of equations:
[tex]4x + 2y = 18\\x-y = 3[/tex]
To solve, we clear "x" from the second equation:
[tex]x = 3 + y[/tex]
We substitute "x" in the first equation:
[tex]4 (3 + y) + 2y = 18\\12 + 4y + 2y = 18\\12 + 6y = 18[/tex]
We clear the value of the variable "y":
[tex]6y = 18-12\\6y = 6\\y = \frac {6} {6}\\y = 1[/tex]
We look for the value of the variable "x":
[tex]x = 3 + y\\x = 3 + 1\\x = 4[/tex]
Thus, the solution of the system is given by:
[tex](x, y) :( 4,1)[/tex]
Answer:
[tex](x, y) :( 4,1)[/tex]
Option D
