A cylinder has a height of 4 inches greater than the radius of its base. Find the radius and the height to the nearest inch if the volume of the cylinder is 5pi cubic inches.

Respuesta :

Answer:

[tex]h=5in, r=1in[/tex]

Step-by-step explanation:

The volume of a cylinder is:

[tex]V=\pi*r^2*h[/tex]

where [tex]r[/tex] is the radius and [tex]h[/tex] is the height.

The height is 4 inches greater that the radius, so:

[tex]h=r+4in[/tex]

Substituting this in the formula for volume:

[tex]V=\pi*r^2*(r+4)[/tex]

the volume is [tex]V=5\pi in^3[/tex]

thus:

[tex]5\pi in^3=\pi*r^2*(r+4in)[/tex]

Dividing everything between pi:

[tex]5in^3=r^2*(r+4in)[/tex]

[tex]5in^3=r^3*+4r^2[/tex]

We can see that the solution for this is [tex]r=1in[/tex]

since [tex](1)^3*+4(1)^2=1+4=5[/tex]

We have the radius, now we find the height:

[tex]h=r+4in=1in + 4in = 5in[/tex]

[tex]h=5in, r=1in[/tex]

Answer:

d

Step-by-step explanation:

just cus