Which figure is the image produced by applying the composition t 0,3 r 0,90 to figure R?






A.


figure H




B.


figure I




C.


figure J




D.


figure R

Which figure is the image produced by applying the composition t 03 r 090 to figure R A figure H B figure I C figure J D figure R class=

Respuesta :

Answer:

Option A is correct

The only figure after composition of [tex]t_{0 , 3} (r_{0,90^{\circ}})[/tex] to figure R is Figure H

Step-by-step explanation:

From the given figure in R;

The coordinates in Figure R ;

(1 , -1) , (2, -2) ,(4, -2) ( 0, -4)

Composite function defined as when one function is substituted into another function.

To Apply the composition [tex]t_{0 , 3} (r_{0,90^{\circ}})[/tex] to figure R;

First apply the Reflection [tex]r_{0, 90^{\circ}}[/tex] in Figure R;

The rule of reflection is given by:

[tex](x,y) \rightarrow (-y,x)[/tex]

By applying the rule of reflection in Figure R ,

then, the coordinates becomes;

(1 , -1) [tex]\rightarrow[/tex] (1, 1)

(2 , -2) [tex]\rightarrow[/tex] (2, 2)

(4 , -2) [tex]\rightarrow[/tex] (2, 4)

(0, -4) [tex]\rightarrow[/tex] (4, 0)

Now, apply the translation [tex]t_{0,3}[/tex]

Translation : It is a type of transformation that moves each point in a figure the same distance in the same direction.

then,

the rule of translation is:

[tex](x,y) \rightarrow (x+0,y+3)[/tex]

Apply the rule of translation on coordinates (1,1) , (2,2),  (2,4) and (4,0)

then

(1 , 1) [tex]\rightarrow[/tex] (1+0 1+3) =(1,4)

(2, 2) [tex]\rightarrow[/tex] (2+0 2+3) =(2, 5)

(2, 4) [tex]\rightarrow[/tex] (2+0 4+3) =(2 ,7) and

(4, 0) [tex]\rightarrow[/tex] (4+0 0+3) =(4 ,3)

Then, the only figure after composition of [tex]t_{0 , 3} (r_{0,90^{\circ}})[/tex] to figure R is Figure H





Answer:

The correct answer is choice A) Figure H