A student increases the temperature of a 556 cm3 balloon from 278 K to 308 K. Assuming constant pressure, what should the new volume of the view be?
a.320 cm3
b.501 cm3
c.1232 cm3
d.616 cm3
from the general gas law pv = nRT since the pressure is constant so V vary with T so, V1/V2 = T1/T2 556/V2= 278/308 so, V2 = (308*556)/(278) V2= 616 cm3 the answer is D
